Résoudre une équation trigonométrique faisant intervenir cos et sin Exercice

S = \left\{ \dfrac{\pi}{3}+k\dfrac{\pi}{3}; \dfrac{3\pi}{4}+k\pi \right\}

S = \left\{ \dfrac{\pi}{12}+k\dfrac{\pi}{3}; \dfrac{3\pi}{4}+k\pi \right\}

S = \left\{ \dfrac{\pi}{6}+k\dfrac{\pi}{3}; \dfrac{3\pi}{4}+k\pi \right\}

S = \left\{ \dfrac{\pi}{12}+k\dfrac{\pi}{3}; \dfrac{3\pi}{4}+2k\pi \right\}

S = \left\{-\dfrac{\pi}{2}+k2\pi;\dfrac{7\pi}{6}+k2\pi\right\}

S = \left\{\dfrac{\pi}{2}+k2\pi;\dfrac{\pi}{6}+k2\pi\right\}

S = \left\{\dfrac{\pi}{2}+k2\pi;\dfrac{7\pi}{6}+k2\pi\right\}

S = \left\{\dfrac{\pi}{3}+k2\pi;\dfrac{7\pi}{6}+k2\pi\right\}

S = \left\{\dfrac{1}{2}+\dfrac{\pi}{8}+2k\pi;-\dfrac{1}{2}+\dfrac{\pi}{8}+2k\pi\right\}

S = \left\{1-\dfrac{\pi}{8}+k\pi;1+\dfrac{\pi}{8}+k\pi\right\}

S = \left\{\dfrac{1}{4}-\dfrac{\pi}{8}+k\pi;\dfrac{1}{4}+\dfrac{\pi}{8}+k\pi\right\}

S = \left\{\dfrac{1}{2}-\dfrac{\pi}{8}+k\pi;\dfrac{1}{2}+\dfrac{\pi}{8}+k\pi\right\}

S = \left\{\dfrac{\pi}{6}+k\dfrac{2\pi}{3};\dfrac{\pi}{2}+k2\pi\right\}

S = \left\{-1+\dfrac{\pi}{3}+k\dfrac{2\pi}{3};1+\dfrac{\pi}{3}+k2\pi\right\}

S = \left\{\dfrac{-1}{3}+\dfrac{\pi}{6}+k\dfrac{2\pi}{3};3+\dfrac{\pi}{2}+k2\pi\right\}

S = \left\{\dfrac{7\pi}{18}+k\dfrac{\pi}{3};\dfrac{11\pi}{18}+k\dfrac{\pi}{3},\right\}

S = \left\{-\dfrac{7\pi}{18}+k\dfrac{2\pi}{3};\dfrac{11\pi}{18}+k\dfrac{2\pi}{3},\right\}

S = \left\{\dfrac{7\pi}{18}+k\dfrac{2\pi}{3};\dfrac{11\pi}{18}+k\dfrac{2\pi}{3},\right\}

S = \left\{\dfrac{7\pi}{18}+k\dfrac{2\pi}{3};-\dfrac{11\pi}{18}+k\dfrac{2\pi}{3},\right\}

S = \left\{ \dfrac{\pi}{6}+k\pi; -\dfrac{\pi}{3}+2k\pi \right\}

S = \left\{ \dfrac{\pi}{6}+k\pi; \dfrac{\pi}{4}+k\pi \right\}

S = \left\{ \dfrac{\pi}{6}+k\pi; \dfrac{\pi}{3}+k\pi \right\}

S = \left\{ -\dfrac{\pi}{6}+k\pi; \dfrac{\pi}{3}+k\pi \right\}