Quel est l'ensemble des solutions de chacune des équations suivantes dans \(\displaystyle{\mathbb{C}}\) ? \(\displaystyle{3iz-2i=4}\) \(\displaystyle{S=\left\{\dfrac{2}{3}-\dfrac{4}{3}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{1}{3}-\dfrac{4}{3}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{2}{3}-\dfrac{1}{3}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{4}{3}-\dfrac{2}{3}i \right\}}\) \(\displaystyle{5i+2iz=1}\) \(\displaystyle{S=\left\{-\dfrac{5}{2}-\dfrac{1}{2}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{1}{2}-\dfrac{5}{2}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{5}{2}-\dfrac{5}{2}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{5}{3}-\dfrac{1}{2}i \right\}}\) \(\displaystyle{-iz+3i=9}\) \(\displaystyle{S=\left\{9i+3 \right\}}\)\(\displaystyle{S=\left\{9i-3 \right\}}\)\(\displaystyle{S=\left\{3i+9 \right\}}\)\(\displaystyle{S=\left\{3i-9 \right\}}\) \(\displaystyle{-4iz-12i=8}\) \(\displaystyle{S=\left\{-3+2i\right\}}\)\(\displaystyle{S=\left\{-3-2i\right\}}\)\(\displaystyle{S=\left\{3+2i\right\}}\)\(\displaystyle{S=\left\{3-2i\right\}}\) \(\displaystyle{3z-i\overline{z}=2i+4}\) \(\displaystyle{S=\left\{\dfrac{7}{4}+\dfrac{5}{4}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{1}{4}+\dfrac{5}{4}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{3}{4}+\dfrac{5}{4}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{9}{4}+\dfrac{5}{4}i \right\}}\) \(\displaystyle{2z+4i\overline{z}=3i-1}\) \(\displaystyle{S=\left\{\dfrac{7}{6}-\dfrac{5}{6}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{7}{6}+\dfrac{5}{6}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{7}{6}-\dfrac{5}{6}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{7}{6}+\dfrac{5}{6}i \right\}}\)
\(\displaystyle{3iz-2i=4}\) \(\displaystyle{S=\left\{\dfrac{2}{3}-\dfrac{4}{3}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{1}{3}-\dfrac{4}{3}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{2}{3}-\dfrac{1}{3}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{4}{3}-\dfrac{2}{3}i \right\}}\)
\(\displaystyle{3iz-2i=4}\) \(\displaystyle{S=\left\{\dfrac{2}{3}-\dfrac{4}{3}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{1}{3}-\dfrac{4}{3}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{2}{3}-\dfrac{1}{3}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{4}{3}-\dfrac{2}{3}i \right\}}\)
\(\displaystyle{5i+2iz=1}\) \(\displaystyle{S=\left\{-\dfrac{5}{2}-\dfrac{1}{2}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{1}{2}-\dfrac{5}{2}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{5}{2}-\dfrac{5}{2}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{5}{3}-\dfrac{1}{2}i \right\}}\)
\(\displaystyle{5i+2iz=1}\) \(\displaystyle{S=\left\{-\dfrac{5}{2}-\dfrac{1}{2}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{1}{2}-\dfrac{5}{2}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{5}{2}-\dfrac{5}{2}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{5}{3}-\dfrac{1}{2}i \right\}}\)
\(\displaystyle{-iz+3i=9}\) \(\displaystyle{S=\left\{9i+3 \right\}}\)\(\displaystyle{S=\left\{9i-3 \right\}}\)\(\displaystyle{S=\left\{3i+9 \right\}}\)\(\displaystyle{S=\left\{3i-9 \right\}}\)
\(\displaystyle{-iz+3i=9}\) \(\displaystyle{S=\left\{9i+3 \right\}}\)\(\displaystyle{S=\left\{9i-3 \right\}}\)\(\displaystyle{S=\left\{3i+9 \right\}}\)\(\displaystyle{S=\left\{3i-9 \right\}}\)
\(\displaystyle{-4iz-12i=8}\) \(\displaystyle{S=\left\{-3+2i\right\}}\)\(\displaystyle{S=\left\{-3-2i\right\}}\)\(\displaystyle{S=\left\{3+2i\right\}}\)\(\displaystyle{S=\left\{3-2i\right\}}\)
\(\displaystyle{-4iz-12i=8}\) \(\displaystyle{S=\left\{-3+2i\right\}}\)\(\displaystyle{S=\left\{-3-2i\right\}}\)\(\displaystyle{S=\left\{3+2i\right\}}\)\(\displaystyle{S=\left\{3-2i\right\}}\)
\(\displaystyle{3z-i\overline{z}=2i+4}\) \(\displaystyle{S=\left\{\dfrac{7}{4}+\dfrac{5}{4}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{1}{4}+\dfrac{5}{4}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{3}{4}+\dfrac{5}{4}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{9}{4}+\dfrac{5}{4}i \right\}}\)
\(\displaystyle{3z-i\overline{z}=2i+4}\) \(\displaystyle{S=\left\{\dfrac{7}{4}+\dfrac{5}{4}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{1}{4}+\dfrac{5}{4}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{3}{4}+\dfrac{5}{4}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{9}{4}+\dfrac{5}{4}i \right\}}\)
\(\displaystyle{2z+4i\overline{z}=3i-1}\) \(\displaystyle{S=\left\{\dfrac{7}{6}-\dfrac{5}{6}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{7}{6}+\dfrac{5}{6}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{7}{6}-\dfrac{5}{6}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{7}{6}+\dfrac{5}{6}i \right\}}\)
\(\displaystyle{2z+4i\overline{z}=3i-1}\) \(\displaystyle{S=\left\{\dfrac{7}{6}-\dfrac{5}{6}i \right\}}\)\(\displaystyle{S=\left\{\dfrac{7}{6}+\dfrac{5}{6}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{7}{6}-\dfrac{5}{6}i \right\}}\)\(\displaystyle{S=\left\{-\dfrac{7}{6}+\dfrac{5}{6}i \right\}}\)