Déterminer sur un quadrillage l'intégrale d'une fonction simple sur un intervalleExercice

\int_{0}^{1} f(x) \, dx = \dfrac{1}{4}

\int_{0}^{1} f(x) \, dx = -\dfrac{1}{2}

\int_{0}^{1} f(x) \, dx = 1

\int_{0}^{1} f(x) \, dx = \dfrac{1}{2}

\int_{0}^{1} f(x) \, dx = 2 

\int_{0}^{1} f(x) \, dx = 3 

\int_{0}^{1} f(x) \, dx = −2 

\int_{0}^{1} f(x) \, dx = \dfrac{1}{6} 

\int_{0}^{1} f(x) \, dx = \dfrac{1}{2} 

\int_{0}^{1} f(x) \, dx = −2

\int_{0}^{1} f(x) \, dx = \dfrac{1}{4} 

\int_{0}^{1} f(x) \, dx = 2

\int_{0}^{1} f(x) \, dx = \dfrac{1}{2}

\int_{0}^{1} f(x) \, dx =4

\int_{0}^{1} f(x) \, dx = \dfrac{1}{4}

\int_{0}^{1} f(x) \, dx =- \dfrac{1}{2}

\int_{0}^{1} f(x) \, dx = − \dfrac{1}{2}

\int_{0}^{1} f(x) \, dx =  \dfrac{1}{2}

\int_{0}^{1} f(x) \, dx = 2

\int_{0}^{1} f(x) \, dx = −2