Dériver un quotient de fonctions affine, carré, cube, inverse, racine carrée et puissanceExercice

\forall x \in \mathbb{R}^* ,  f'(x) = 2

\forall x \in \mathbb{R}^* ,  f'(x) = \dfrac{4x+3}{x^2}

\forall x \in \mathbb{R}^* ,  f'(x) = 4x+3

\forall x \in \mathbb{R}^* ,  f'(x) = -\dfrac{3}{x^2}

\forall x \in \mathbb{R}\backslash\{4\} , f'(x) = \dfrac{−2x^2+10x−8}{(-x+4)^2}

\forall x \in \mathbb{R}\backslash\{4\} , f'(x)= \dfrac{−5}{(-x+4)^2}

\forall x \in \mathbb{R}\backslash\{4\} , f'(x) = \dfrac{-x^2+8x−5}{(-x+4)^2}

\forall x \in \mathbb{R}\backslash\{4\} , f'(x) = \dfrac{8x−5}{(-x+4)^2}

\forall x \in \mathbb{R}^*_+ , f'(x)= \dfrac{-\frac{5}{\sqrt{x}}}{x}

\forall x \in \mathbb{R}^*_+ , f'(x)= \dfrac{−5}{x\sqrt{x}}

\forall x \in \mathbb{R}^*_+ , f'(x)= \dfrac{3x−5}{2x\sqrt{x}}

\forall x \in \mathbb{R}^*_+ , f'(x)= \dfrac{\frac{3}{2}\sqrt{x}-\frac{5}{2\sqrt{x}}}{x}

\forall x \in \mathbb{R}^*_+ , f'(x)= \dfrac{1}{4x^3\sqrt{x}}

\forall x \in \mathbb{R}^*_+ , f'(x)= \dfrac{5x^4}{x^4\sqrt{x}}

\forall x \in \mathbb{R}^*_+ , f'(x)= \dfrac{−7}{x^4\sqrt{x}}

\forall x \in \mathbb{R}^*_+ , f'(x)= \dfrac{−5x^4}{x^4\sqrt{x}}

\forall x \in \mathbb{R}\backslash\{0;−2\} , f'(x)= \dfrac{x+1}{x^2(x+2)^2}

\forall x \in \mathbb{R}\backslash\{0;−2\} , f'(x)= \dfrac{x^2+x+2}{x^2(x+2)^2}

\forall x \in \mathbb{R}\backslash\{0;−2\} , f'(x)= \dfrac{−2x^2−2x+4}{x^2(2x+4)^2}

\forall x \in \mathbb{R}\backslash\{0;−2\} , f'(x)= \dfrac{x+1}{2x^2(x+2)^2}